b^2=49b2=49

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Solution for b^2=49b2=49 equation: 



b^2=49b^2=49

We move all terms to the left:

b^2-(49b^2)=0

We add all the numbers together, and all the variables

-48b^2=0

a = -48; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-48)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{-96}=0$

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